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68x^2-9x-2=0
a = 68; b = -9; c = -2;
Δ = b2-4ac
Δ = -92-4·68·(-2)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-25}{2*68}=\frac{-16}{136} =-2/17 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+25}{2*68}=\frac{34}{136} =1/4 $
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